CertifQ

OPTIONS 0.66 0.62 0.6 0.5 ANSWER 0.66 EXPLANATION Applying standard binomial formula with p = 0.02 and x = 0.

i. The process is in control ii. The process may not have been in control iii. The process may not have been normal OPTIONS i and ii ii and iii i, ii and iii Correct Option:B ii and iii EXPLANATION Such a condition can only...

ANSWER Reduce variations Center the mean Bring the process in statistical control The choice of what to do rests with the Black Belt ANSWER Reduce variations EXPLANATION Cp value less than 1 automatically indicates that variations are high in the process

OPTIONS 0.5 1 1.5 2 ANSWER 1 EXPLANATION The Cp is 1 as derived by applying standard Cp formula.

OPTIONS Choose normal after transforming data Choose 3-Parameter Weibull Choose Log-Normal Can’t decide ANSWER Choose normal after transforming data EXPLANATION The Box Cox distribution has the best fit value here. So, the Black Belt should transform the data.

OPTIONS The data is normal bar one or two exceptions The data may not follow a normal distribution The Box Cox transformation should be used to check the fit The data may have to be subjected to further tests. ANSWER The data may not follow...

OPTIONS The process is stable The process seems to be capable on specification The process is capable on target The process could be unstable, and the degree of confidence on future stability is low ANSWER The process could be unstable, and the degree of confidence...

OPTIONS 4 4/Square root(33) Cannot determine 2 ANSWER 4 EXPLANATION Sample mean = Population mean by CLT

OPTIONS Baseline then do MSA MSA then do Baseline Baseline then do MSA then do re-MSA No specific flow as such and depends on the decision of the Black Belt ANSWER Baseline then do MSA then do re-MSA EXPLANATION Baselining should always be done twice...

OPTIONS Resolution Accuracy Linearity Bias ANSWER Resolution EXPLANATION Resolution is the other name for Discrimination thus a is correct.