A. 0.007B. 0.00655C. 0.0062D. 0.0055 0.0062 Z = (150-125)/10 = 25/10 = 2.5 Area under 2.5 corresponds to 0.0062. Thus, the probability of a Type II Error, which is beta, is 0.62%.
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A. A type I error improves with each individual analysisB. Interactions are clearly determinedC. A type I error increases with each individual analysisD. The optimum combination of factors is revealed A type I error increases with each individual analysis With each single comparison, more errors...
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A. Simplex designsB. Orthogonal designsC. Screening experimentsD. Mixture experiments Screening experiments In screening experiments, highly fractional factorial designs are used to look for only factor main effects. They are called screening because they try to eliminate seemingly unimportant factors.
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A. CollinearityB. ConfoundedC. CorrelationD. Covariates Collinearity Having two variables that are highly correlated in the experimental model will make it difficult or impossible to detect which factor really affects the response. This condition is called collinearity. The correct answer is Collinearity .
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Full factorial Half fractional factorial Quarter fractional factorial None of the above Quarter fractional factorial Quarter fractional factorial is an experiment where three quarters of the combinations are omitted.
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Brainstorming Multi-voting NGT Discussions Multi-voting can at times be used as a substitute to Pareto charts as a prioritization tool. Option b is the correct answer.
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They don’t normally give the right results They mislead the practitioners at times The results may be statistically significant in cases, but the practical significance need to be known. They are too biased on errors The results may be statistically significant in cases, but the...
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exchange error estimate expected exchange SMED stands for Single Minute Exchange of Die which means the Die should be exchanged in not more than 9 minutes. So, a is the right answer.
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Replication Blocking Randomization Coding Blocking By creating blocks in an experiment, you can eliminate the errors due to nuisance factors and thus option b is the correct answer.
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0.85 0.8 0.9 0.75 0.85 P(A or B) = P(A) + P(B)-P(A&B) = 0.6+0.5-0.25 = 0.85. Thus, option a is the correct option.
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